Math

• Notes
• HW 2.6
• HW 2.7
• HW 3.1
• HW 3.2
• HW 3.3
• HW 3.4
• HW 3.5
• HW 4.1
• HW 4.2
• HW 4.3
• HW 4.4
• HW 4.5
• Exam November 9th
• Exam November 9th Corrections
• Test Review 03-08-2016

• Chem 7.31 - 7.45

HW4.1 Q10

$A = P(1+\frac{r}{n})^{nt}$

$A =Pe^{rt}$

$P =25,000$
$r = 0.06$
$t=6$

$n=2$

$A=25000(1+\frac{0.06}{2})^{2\cdot6}$

$A=25000(1+0.03)^{2\cdot6}$
$=25000(1.03)^{12}$
$=\color{blue}{35,644.02}$

$n=4$

$A=25000(1+\frac{0.06}{4})^{4\cdot6}$

$A=25000(1+0.015)^{4\cdot6}$
$=25000(1.015)^{24}$
$=\color{blue}{35,737.57}$

$n=12$

$A=25000(1+\frac{0.06}{12})^{12\cdot6}$

$A=25000(1+0.015)^{12\cdot6}$
$=25000(1.005)^{72}$
$=\color{blue}{35,801.11}$

$A= 25,000(e^{0.06\cdot6})$

$=25,000(e^{0.36}) \\=\color{blue}{35,833.24}$

HW4.1 Q11

$A = P(1+\frac{r}{n})^{nt}$

$A =Pe^{rt}$

$P =14,000$
$r = 0.09$
$t=5$
$n=4$

$A=14000(1+\frac{0.09}{4})^{4\cdot5}$

$A=14000(1+0.0225)^{4\cdot5}$
$=14000(1.0225)^{20}$
$=\color{blue}{21,847.13}$

$P =14,000$
$r = 0.0888$
$t=5$

$A =Pe^{rt}$

$A= 14,000(e^{0.0888\cdot5})$

$=14,000(e^{0.444}) \\=\color{blue}{21,825.03}$

HW4.1 Q13

$S =C(1+r)^t$

$C=145,000$
$r=0.06$
$t=15$

$S=145,000(1+0.06)^{15}$
$=34,7500.94$
$=\color{blue}{34,7501}$

HW4.1 Q14

$f(x)=0.17x+1.13$

$g(x)=1.74e^{0.0476x}$

$f(40) = 0.17(40)+1.13$
$= 7.93$

$g(40)=1.74e^{0.0476(40)}$
$=11.7$

HW4.1 Q15

$f(x)=90e^{-0.5x}+10$

$f(0)=90e^{-0.5(0)}+10$
$=90e^0+10\\=\color{blue}{100}$

$f(1)=90e^{-0.5(1)}+10$
$=\color{blue}{64.6}$

$f(8)=90e^{-0.5(8)}+10$
$=\color{blue}{11.6}$

$f(52)=90e^{-0.5(52)}+10$
$=\color{blue}{10.0}$

HW4.1 Q16

$f(x)=70e^{-0.7x}+30$

$f(0)=70e^{-0.7(0)}+30$
$=70(1)+30\\=\color{blue}{100}$

$f(1)=70e^{-0.7}+30$
$=\color{blue}{64.8}$

$f(4)=70e^{-0.7(4)}+30$
$=\color{blue}{34.3}$

$f(52)=70e^{-0.7(52)}+30$
$=\color{blue}{30}$

HW4.1 Q17

$f(x)=60e^{-0.4x}+40$

$f(0)=60e^{-0.4(0)}+40$
$=60(1)+40\\=\color{blue}{100}$

$f(1)=60e^{-0.4}+40$
$=\color{blue}{80.2}$

$f(4)=60e^{-0.4(4)}+40$
$=\color{blue}{52.1}$

$f(52)=60e^{-0.4(52)}+40$
$=\color{blue}{40}$

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